
Bila
diketahui mA
= 20 kg ,mB = 40 kg, dan koefisien gesekan 0,25. Hitunglah
Percepatan mA dan mB !. ( Massa dan gesekan kedua katrol
diabaikan).
Jawaban :
Benda A
ƩFy = 0
N - WA = 0
N = MA x g……………………………………..(1)
ƩFx = MA x aA
T1 – fges = MA
x aA
T1 = (µges MA x g )+( MA x aA )…………..........(2)
Katrol 2
ƩFkatrol = Mkatrol
x akatrol
T2’ – 2T1 =
0
Dimana T2’ = T2
T2 =...